During reversible adiabatic process, the pressure of a gas is found to be proportional to the cube of its absolute temperature.The ratio (C_(p))/(C_(v)) for the gas is

During reversible adiabatic process, the pressure of a gas is found to

1.	During reversible adiabatic process, the pressure of a gas is found to be proportional to the cube of its absolute temperature.The ratio (C_(p))/(C_(v)) for the gas is
Answer» `3/2` `7/2` `5/3` `9/7` Solution :According to the PROBLEM, `P infty T^(3)` or `P = KT^(3) or PT^(-3) = K` ....(i) For a reversible adiabatic process. `T^(GAMMA) P^(1-gamma) = k` `(gamma)/(T^(1 - gamma)) P = k`...(II) Compairing eq.(i) and (ii) `(gamma)/(1 - gamma) = -3` or `gamma = -3 + 3gamma` or `-2gamma = -3 or gamma = 3/2`.