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During the electrolysis of `AgNO_(3)`, the volume of `O_(2)` formed at `STP` due to passage of `2A` of current for `965 s` isA. `0.112L`B. `0.224L`C. `11.2L`D. `22.4L` |
Answer» Correct Answer - a Number of Faradays `=(It)/(96500)=(2xx9650)/(96500)=0.02` Anode `:2H_(2)O(l) rarr O_(2)(g)+4H^(o+)(aq)+4e^(-)` `implies4F` electricity `=1 mol O_(2)-=22.4L O_(2)` at `STP` `implies0.2F` electricity `=22.4xx(0.02)/(4)` `=0.112L O_(2)` at `STP` |
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