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During the first `18 min` of a `60 min` trip, a car has an average speed of `11 ms^-1.` What should be the average speed for remaining `42 min` so that car is having an average speed of `21 ms^-1` for the entire trip?A. `25.3 ms^-1`B. `29.2 ms^-1`C. `31 ms^-1`D. `35.6 ms^-1` |
Answer» Correct Answer - A `v_(av)=d/t=(d_1+d_2)/(t_1+t_2)` `21=((18)(11)+(42)(v))/60` `rArr v=25.3m//s` |
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