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During the quation analysis of a mixture containing `Cu^(2+) and Zn^(2+) ions H_(2)S` gas is passed therough an acidified solution containing these ions in order to test `Cu^(2+)` alone explane |
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Answer» `H_(2)S hArr 2H^(o+) +S^(2-)` `HCI rarr H +CI^(Theta)` `K_(sp) `(solubility product) of `CuS` is less than `K_(sp)` of `ZnS `.Due to common ion effect ,the ionisation of `H_(2)S` is sappressed and the `S^(2-)` concentration decreases Only those metal sulphides get precipitate which have low `K_(sp)` so ZnS is not precipitate. |
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