`(dy)/(dx) + 2 y tan x = sin x `

1.	`(dy)/(dx) + 2 y tan x = sin x `
Answer» Correct Answer - `y = cos x + C cos ^(2) x` `IF = e^ ( int 2 tan x dx ) = e ^(-2 log cos x ) = e ^(log (cos x ) ^(-2)) = (cos x) ^(-2) = (1)/(cos ^(2) x)` ` y xx (1)/(cos^(2) x) = int { sinx xx (1)/(cos ^(2) x )} dx +C = int sec x tan x dx +C = sec x +C ` ` therefore y =cos x + C cos ^(2)x `

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