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Answer»

Given polynomialx^2 + x/6 - 2 = 06x^2 + x - 12 = 06x^2 + 9x - 8x - 12 = 03x(2x + 3) - 4(2x + 3) = 0(3x - 4)(2x + 3) = 0x = 4/3, - 3/2

For polynomial of formax^2 + bx + c = 0

Sum of zeroes = 4/3 - 3/2 = (8-9)/6 = - 1/6- b/a = - 1/6

Product of zeroes= 4/3*-3/2 = - 2c/a = - 12/6 = - 2



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