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`(e^(2x)-1)/(e^(2x)+1)`

Answer» `int(e^(2x-1)/(e^(2x)+1))dx" माना "e^(x)+e^(-x)=t`
`=int(e^(x)-x^(-x))/(e^(x)+e^(-x))dx=int(1)/(t)dt" "rArr (e^(x)-e^(-x))dx=dt`
`=log|t|+c=log|e^(x)+e^(-x)|+c`


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