`E^(c-)` for `Cr^(3+)+3e^(-) rarr Cr `and `Cr^(3+)+e^(-) rarr Cr^(2+)` are `-0.74 V` and `-0.40V`, respectively, `E^(c-)` for the reaction is `Cr^(+2)+2e^(-) rarr Cr`A. `-0.91V`B. `+0.91V`C. `-1.14V`D. `+0.34V`

`E^(c-)` for `Cr^(3+)+3e^(-) rarr Cr `and `Cr^(3+)+e^(-) rarr Cr^(2+)`

1.	`E^(c-)` for `Cr^(3+)+3e^(-) rarr Cr `and `Cr^(3+)+e^(-) rarr Cr^(2+)` are `-0.74 V` and `-0.40V`, respectively, `E^(c-)` for the reaction is `Cr^(+2)+2e^(-) rarr Cr`A. `-0.91V`B. `+0.91V`C. `-1.14V`D. `+0.34V`
Answer» Correct Answer - a `Cr^(3+)+3e^(-) rarr Cr,` `Cr^(3+)+e^(-) rarr Cr^(2+), ` `ulbar(Cr^(2+)+2e^(-) rarr Cr,)` `E^(c-)._(3)=(n_(1)E^(c-)._(1)-nE^(c-)._(2))/(n_(3))` `=([3xx(-0.74)]-[(-1)xx(-0.40)])/(2)=-0.91V`

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