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e figure 10.15, show that:ABII CDCD II EFAB II EFfy your answer.407 B1602020°Fig. 10.15 |
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Answer» since angle ABC = 40 = Angle ( BCE+ECD) , so these makes alternate interior angle..so AB || CD now angle ECD + angle CEF = 20°+ 160° = 180° (adjacent angles) so EF||CD and because CD is parallel to both AB and EF SO, AB||EF |
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