1.

E^(@) for CL_(2)//Cl^(-)=+1.36,I_(2)//I^(-)=+0.53,Ag^(+)//Ag=+0.79,Na^(+)//Na=-2.71 and Li^(+)//Li=-3.04V. What is the order of decreasing reducing sterngth for these species?

Answer»

`LI GT Cl^(-) gt AG gt I^(-) gt Na`
`Li gt Na gt I^(-) gt Ag gt Cl^-`
`Cl^(-) gt Ag gt I^(-) gt Na gt Li`
`Na gt Li gt Ag gt Cl^(-) gt I^(-)`

SOLUTION :The order is `Li gt Na gt I^(-) gt Ag gt Cl^(-)`


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