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`E^(@)` for `F_(@)+2e hArr2F^(-)` is `2.7 V` Thus, `E^(@)` for `F^(-) hArr(1)/(2)Fe +e` is :A. `1.35 V`B. `-1.35 V`C. `-2.7 V`D. `2.7 V` |
Answer» Correct Answer - C `E_(OP)^(@) = -E_(RP)^(@)` |
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