`E^(@)` for the cell `Zn(s)|Zn^(2+)(aq)|Cu^(2+)(aq)|Cu(s)` is 1.1V at `25^(@)C` the equilibrium constant for the cell reaction is aboutA. `10^(-37)`B. `10^(37)`C. `10^(73)`D. `10^(73)`

`E^(@)` for the cell `Zn(s)|Zn^(2+)(aq)|Cu^(2+)(aq)|Cu(s)` is 1.1V at

1.	`E^(@)` for the cell `Zn(s)\|Zn^(2+)(aq)\|Cu^(2+)(aq)\|Cu(s)` is 1.1V at `25^(@)C` the equilibrium constant for the cell reaction is aboutA. `10^(-37)`B. `10^(37)`C. `10^(73)`D. `10^(73)`
Answer» Correct Answer - B At 298k, `E^(@)=(0.0591)/(n)"log"k` `1.1=(0.0591)/(2)"log"k` (Here n=2) log `k=(1.1xx2)/(0.0591)=37.22` `k="antilog" 37.22=1.65xx10^(37)`

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`E^(@)` for the cell `Zn(s)|Zn^(2+)(aq)|Cu^(2+)(aq)|Cu(s)` is 1.1V at `25^(@)C` the equilibrium constant for the cell reaction is aboutA. `10^(-37)`B. `10^(37)`C. `10^(73)`D. `10^(73)`

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