E∘ for the cell, Zn(s)|Zn2+(aq)||Cu2+(aq)|Cu(s) is 1.10 V at 25� – InterviewSolution

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1.	E∘ for the cell, Zn(s)\|Zn2+(aq)\|\|Cu2+(aq)\|Cu(s) is 1.10 V at 25∘C. The equilibrium constant for the reaction, Zn(s)+Cu2+(aq)→Cu(s)+Zn2+(aq) is 1.94×10x. The value of x is
Answer» $E^{\circ}$ for the cell, ${Zn(s)\|Zn}^{2 +} (aq) \| \| {Cu}^{2 +} (aq)\|Cu(s)$ is $1.10$ V at $25^{\circ} C$ . The equilibrium constant for the reaction, $Zn(s) + {Cu}^{2 +} (aq) \to Cu(s) + {Zn}^{2 +} (aq)$ is $1.94 \times 10^{x}$ . The value of $x$ is

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