E∘ for the cell Zn|Zn2+(aq)||Cu2+(aq)|Cu) is 1.10 v at 25∘. The eq – InterviewSolution

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1.	E∘ for the cell Zn\|Zn2+(aq)\|\|Cu2+(aq)\|Cu) is 1.10 v at 25∘. The equilibrium constant for the reactionZn+Cu2+(aq)→Cu+Zn2+(aq) is of the order of:
Answer» $E^{\circ}$ for the cell $Z n \| Z n^{2 +} (a q) \| \| C u^{2 +} (a q) \| C u)$ is $1.10 v$ at $25^{\circ}$ . The equilibrium constant for the reaction $Z n + C u^{2 +} (a q) \to C u + Z n^{2 +} (a q)$ is of the order of:

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