`E^(@)(Ni^(2+)//Ni) =- 0.25` volt, `E^(@)(Au^(3+)//Au) = 1.50` volt. The emf of the voltaic cell `Ni|Ni^(2+) (1.0M)||Au^(3+)(1.0M)|Au` is:-A. `1.25` voltB. `-1.75` voltC. `1.75` voltD. `4.0`volt

`E^(@)(Ni^(2+)//Ni) =- 0.25` volt, `E^(@)(Au^(3+)//Au) = 1.50` volt. T

1.	`E^(@)(Ni^(2+)//Ni) =- 0.25` volt, `E^(@)(Au^(3+)//Au) = 1.50` volt. The emf of the voltaic cell `Ni\|Ni^(2+) (1.0M)\|\|Au^(3+)(1.0M)\|Au` is:-A. `1.25` voltB. `-1.75` voltC. `1.75` voltD. `4.0`volt
Answer» Correct Answer - C `E_("cell")^(@)= E_("cathod")^(@)-E_("anode")^(@)=1.50 - (-0.25)= 1.75 V`

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`E^(@)(Ni^(2+)//Ni) =- 0.25` volt, `E^(@)(Au^(3+)//Au) = 1.50` volt. The emf of the voltaic cell `Ni|Ni^(2+) (1.0M)||Au^(3+)(1.0M)|Au` is:-A. `1.25` voltB. `-1.75` voltC. `1.75` voltD. `4.0`volt

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