E^(Ө) values of some redox couples are given below, On the basis of these values choose the correct option. E_(Br_(2)//Br^(-))^(Ө)=+1.90"volt",E_(Ag^(+)//Ag_((s)))^(Ө)=+0.80"volt" E_(Cu^(+2)//Cu_((s)))^(Ө)=+0.34"volt",E_(I_(2(s))//I^(-))^(Ө)=+0.54"volt"

E^(Ө) values of some redox couples are given below, On the basis of t

1.	E^(Ө) values of some redox couples are given below, On the basis of these values choose the correct option. E_(Br_(2)//Br^(-))^(Ө)=+1.90"volt",E_(Ag^(+)//Ag_((s)))^(Ө)=+0.80"volt" E_(Cu^(+2)//Cu_((s)))^(Ө)=+0.34"volt",E_(I_(2(s))//I^(-))^(Ө)=+0.54"volt"
Answer» Cu will reduced `BR^(-)` Cu will reduced Ag Cu will reduced `I^(-)` Cu will reduced `Br_(2)` SOLUTION :Given FOLLOWING VALUES : `Br_(2)//Br^(-)=+1.90V," "Ag//Ag^(+)=-0.80V` `Cu^(+2)//Cu(s)=+0.34V," "I^(-)//I_(2)(s)=-0.54V,` `Br^(-)//Br_(2)=-1.90V` Cu is reduced `Br_(2)`, So VALUE of `E_("cell")^(Ө)` will be positive.