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InterviewSolution
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e percentage composition of an organic compound found to contain39.9% carbon, 6.7% hydrogen and the rest is oxygen. If the molecular mass7) a] Thof the compound is 60gmol1. Determine the molecular formula of the4 |
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Answer» In 100 g of the unknown, there are40.0⋅g12.011⋅g⋅mol−1C;6.7⋅g1.00794⋅g⋅mol−1H; and53.5⋅g16.00⋅g⋅mol−1O. We divide thru to get,C:H:O=3.33:6.65:3.34. When we divide each elemental ratio by the LOWEST number, we get an empirical formula ofCH2O, i.e. near enough to WHOLE numbers. Now the molecular formula is always a multiple of the empirical formula; i.e.(EF)n=MF. So60.0⋅g⋅mol−1=n×(12.011+2×1.00794+16.00)g⋅mol−1. Clearlyn=2, and the molecular formula is2×(CH2O)=CxHyOz. |
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