InterviewSolution
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InterviewSolution
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`E^(θ)` values of some redox couples are given below. On the basis of these values choose the correct option. `E^(θ)` values: `Brt_(2)//Br^(-) = +1.90` `Ag^(+)//Ag(s)=+0.80` `Cu^(2+)//Cu(s)=+0.34, I_(2)(s)//I^(-)=+0.54`A. Cu will reduce `Br^(-)`B. Cu will reduce AgC. Cu will reduce `I^(-)`D. Cu will reduce `Br_(2)` |
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Answer» Correct Answer - d Given that `E^(@)` values of `Br//Br^(-)=+1.90V` `Ag//Ag^(+)=-0.80V` `Cu^(2+)//Cu(s)=+0.34V` `I^(-)//I_(2)(s)=0.54V` `Br^(-)//Br_(2)=-1.90V` The `E^(@)` values show that copper will reduce `Br_(2)`, If the `E^(@)` of the following redox reaction is positive. `2Cu+Br_(2)toCuBr_(2)` Now, `CutoCu^(2+)+2e^(-), E^(@)=-0.34V` `(Br_(2)+2e^(-)to2Br^(-), E=+1.09V)/(Cu+2Br_(2)toCuBr_(2),E^(@)=+0.75V)` Since, `E^(@)` of this reaction is positive, therfore, Cu can reduce `Br_(2)`. While other reaction will give negative value. |
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