E^(@) values of some redox couples are given below on the basic of these values choose the correct option option E^(@) values : Br_(2)/Br^(-)=1.09 Ag^(+)//Ag(s)=+0.80,Cu^(2+)//Cu(s)=+0.34 I_(2)(s)//(I)^(-)=+0.54

E^(@) values of some redox couples are given below on the basic of the

1.	E^(@) values of some redox couples are given below on the basic of these values choose the correct option option E^(@) values : Br_(2)/Br^(-)=1.09 Ag^(+)//Ag(s)=+0.80,Cu^(2+)//Cu(s)=+0.34 I_(2)(s)//(I)^(-)=+0.54
Answer» Solution :Copper will REDUCE `Br_(2)` if the `E^(@)` of the redox reactoin `2Cu +Br_(2)rarr CuBr_(2)` is +ve <BR> `Cu rarrCu^(2+)+2e^(-),E^(@)=-0.34V` `Br_(2)+2e^(-)rarr2 Br^(-), E^(@)=+1.09 V` `Cu+Br_(2)rarrCuBr_(2),E^(@)=+0.75 V` Since `E^(@)` of this REACTIONIS +ve therefore Cu can reduce `Br_(2)` and henc eoption (d) is CORRECT