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E1:x2a2+y2b2−1=0,(a>b) and E2:x2k2+y2b2−1=0,(k<b) is inscribed in E1. If E1 and E2 have same eccentricities and length of minor axis of E2=p×LLR of E1, then p= |
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Answer» E1:x2a2+y2b2−1=0,(a>b) and E2:x2k2+y2b2−1=0,(k<b) is inscribed in E1. If E1 and E2 have same eccentricities and length of minor axis of E2=p×LLR of E1, then p= |
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