Each of two men A and B is carrying a source of sound of frequency n . If A approaches B with a velocity u how many beats per second will be heard by B ? (Velocity of sound = c)

Each of two men A and B is carrying a source of sound of frequency n .

1.	Each of two men A and B is carrying a source of sound of frequency n . If A approaches B with a velocity u how many beats per second will be heard by B ? (Velocity of sound = c)
Answer» <html><body><p></p>Solution :Apparent frequency , n. ` (<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> + u_(0))/(c- u_(5)) xx n`<br/>The distance between A and B is dacreasing . So , the velocity of the listener ` u_(0) ` and that of the source ` u_(s) ` , are both positive<br/>When B is the listener, velocity of the listener, ` u_(0)=0 `,<br/> Velocity of the source ` A , u_(s)= u `<br/> So, ` n_(8) = (c) /(c-u) xxn `<br/> Evidently, ` n_(8) <a href="https://interviewquestions.tuteehub.com/tag/gt-1013864" style="font-weight:bold;" target="_blank" title="Click to know more about GT">GT</a> n`<br/> ` therefore ` Number of beats <a href="https://interviewquestions.tuteehub.com/tag/per-590802" style="font-weight:bold;" target="_blank" title="Click to know more about PER">PER</a> <a href="https://interviewquestions.tuteehub.com/tag/second-1197322" style="font-weight:bold;" target="_blank" title="Click to know more about SECOND">SECOND</a><br/> ` therefore ` Number of beats per second<br/> ` n_(g) - n = ((c)/(c- u) -1)xx n = (u)/(c-u) n`</body></html>