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Each second a rabbit moves half the remaining distance from his nose to a carrot. (a) Does he ever get to the carrot?(b) What is the limiting value of his average velocity? |
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Answer» (a) If x0 be the initial distance between nose of the rabbit and carrot, then distance between them after first, second, third, fourth,.... Second will be, x0/2, x0/4,x9/8, x0/16.......respectively. Thus, the distance left, after n second. x = x0 (1/2 + 1/22 +1/23 +1/24 +......) or, x = x0e-At. Putting the initial values, x = x0/2 and t = 1, we get x0/2 = x0 A-A or, = loge (2) = 0.693. The position of the rabbit with respect to carrot at any time t, will be given as x = x0e0.693t For reaching x = 0, 0 = x = x0e-0.693t ⇒ t = ∝ It meant rabbit will never reach the carrot. (b) The average velocity = distance travelled/time taken = x0/α = 0 The limiting value of average velocity is zero. |
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