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Answer» ABCD is a quadrilateral and AC and BD are diagonals .Sum of two sides of triangle is greater than the 3rd side So.. considering the triangle ABC ,BCD , CAD, BAD ...We get AB + BC > ACCD +AD >ACAB +AD>BD BC+CD >BD..... adding all above the equations , 2(AB+ BC + CA + AD ) > 2(AC + BD )i.e. (AB +BC + CA + AD ) > (AC+ BD ) |
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