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Efficiency of a heat engine whose sink is at temperature of 300 K is 40% . To increase the efficiency to 60 % keeping the sink temperature same, the source temperature must be increased by |
Answer» <html><body><p></p>Solution :`(T_(2))/(T_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>))=1-eta=1-(40)/(<a href="https://interviewquestions.tuteehub.com/tag/100-263808" style="font-weight:bold;" target="_blank" title="Click to know more about 100">100</a>)=(3)/(5)` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/rarr-1175461" style="font-weight:bold;" target="_blank" title="Click to know more about RARR">RARR</a> T_(1)=(5)/(3)T_(2) rArr T_(1)=(5)/(3)xx300=500K` <br/> New efficiency `eta=60%` <br/> `(T_(2))/(T_(1))=1-eta=1-(60)/(100)=(2)/(5)""T_(1)=(5)/(2)xx300=750K`, <br/> `DeltaT=750-500=250K`</body></html> | |