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Eger type questions.The ratio of the lengths of two rods is 4:3. The ratio of their coefficients of cubical expansion is 2ratio3 Then the ratio of their linear expansion when they are heated through same temperature difference is x ratio 9.then x value​

Answer»

ANSWER:

the relation between cubical expansion coefficient and linear expansion coefficient is,

\gamma  = 3\alphaγ =3α

Thus,

\frac{{{\alpha _1}}}{{{\alpha _2}}} = \frac{{{\gamma _1}}}{{{\gamma _2}}}=\frac{2}{3} α 2α 1 = γ 2γ 1 = 32

​                            The linear expansion is GIVEN as,

\Delta l = \alpha l\Delta TΔl=αlΔT

Therefore,

\frac{{\Delta {l_1}}}{{\Delta {l_2}}} = \LEFT( {\frac{{{\alpha _1}}}{{{\alpha _2}}}} \right) \TIMES \frac{{{l_1}}}{{{l_2}}}

Δl 2Δl 1=( α 2α 1 )× l 2l 1

​= \frac{2}{3} \times \frac{4}{3} = \frac{8}{9}= 32× 34= 98

​

                          THIS IS YOUr  ANSWER


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