Eight equal drops of water are falling through air with a steady velocity of 0.1 ms^(-1) combine to form a single drop, what should be the new terminal velocity.

Eight equal drops of water are falling through air with a steady veloc

1.	Eight equal drops of water are falling through air with a steady velocity of 0.1 ms^(-1) combine to form a single drop, what should be the new terminal velocity.
Answer» Solution :Let v be the terminal velocity of each small drop and the terminal velocity of the bigger drop ` "" (V)/(v)= (R^(2))/( r^(2))` VOLUME of one BIG drop - Volume of 8 drops ` "" (4)/(3)pi R^(3)= 8 xx (4)/(3) pi r^(3)` ` "" R = 2r` ` ""( R^(2))/( r^(2))= 4 ` Substituting in equation (1) ` ""(V)/(v)= 4 , V = 4 xx v =4 xx 0.1 = 0.4 ms^(-1)`