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Eight years ago, the ratio of the ages of A and B was 9 ∶ 10. The ratio of their ages 4 years from now will be 12 ∶ 13. If the age of C is 4 years less than the present age of A, then what is the present age (in years) of C?1. 482. 443. 524. 40 |
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Answer» Correct Answer - Option 4 : 40 Given: Eight years ago ages of A and B is 9 : 10. Four years now the ratio of Ages of A and B is 12 ∶ 13 The age of C is 4 years less than the present age of A. Concept used: By ratio method. Calculation: Let eight years ago age of A be 9x years Eight years ago age of B be 10x years Present age, A's age = 9x + 8 B's age = 10x + 8 After four year, A's age = 9x + 8 + 4 = 9x + 12 B's age = 10x + 8 + 4 = 10x + 12 According to the question, (9x + 12)/(10x + 12) = 12/13 ⇒ 117x + 156 = 120x + 144 ⇒ 3x = 12 ⇒ x = 4 So, Present age of A = 9x + 8 = 9 × 4 + 8 = 44 The present age of C = 4 years less than the present age of A ⇒ Present age of C = 44 – 4 = 40 ∴ The Present age of C is 40 years. |
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