एक 5 सेमी लम्बाई की वस्तु 40 स

1.	एक 5 सेमी लम्बाई की वस्तु 40 सेमी फोकस दूरी वाले उत्तल लेंस के सामने मु्ख्य अक्ष पर 20 सेमी की दूरी पर रखी है । लेंस द्वारा बने प्रतिबिम्ब की स्थिति, प्रकृति एवं आकार ज्ञात कीजिए । निम्न आरेख भी खींचिए ।
Answer» EXPLANATION: U = -40cm I = 5cm f = 20cm 1/u + 1/V = 1/f 1/-40 + 1/v = 1/20 1/v = 1/20 + 1/40 1/v =3/40 v = 40/3cm = $13 \times \frac{1}{3} cm \\ \ \\$ I/O = -v/u 5/O = -13.333 /-40 O = 5/(-13.33/40) O = 0.0093cm

एक 5 सेमी लम्बाई की वस्तु 40 सेमी फोकस दूरी वाले उत्तल लेंस के सामने मु्ख्य अक्ष पर 20 सेमी की दूरी पर रखी है । लेंस द्वारा बने प्रतिबिम्ब की स्थिति, प्रकृति एवं आकार ज्ञात कीजिए । निम्न आरेख भी खींचिए ।

Answer»

EXPLANATION:

U = -40cm

I = 5cm

f = 20cm

1/u + 1/V = 1/f

1/-40 + 1/v = 1/20

1/v = 1/20 + 1/40

1/v =3/40

v = 40/3cm =

$13 \times \frac{1}{3} cm \\ \ \\$

I/O = -v/u

5/O = -13.333 /-40

O = 5/(-13.33/40)

O = 0.0093cm

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