InterviewSolution
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एक यादृच्छिक चर X का प्रायिकता बंटन निम्न्वत है- ज्ञात कीजिए- (i) k (ii) `P(Xgt3)` (iii) `P(Xgt6)` (iv) `P(0ltXlt3)` |
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Answer» Correct Answer - `(i) (1)/(10), (ii) (1)/(2), (iii) (17)/(100), (iv) (13)/(10)` (i) `overset(7)underset(x=0)Sigmap(k)=1` `rArr" "k+2k+2k+3k+2k^(2)+k^(2)+7k^(2)+k=1` `rArr" "10k^(2)+9k-1=0` `rArr" "(10k-1)(k+1)=0` `rArr" "k=(1)/(10)" या "k=-1` `because k` ऋणात्मक नहीं हो सकता इसलिए `k=(1)/(10)` (ii) `P(Xgt3)=P(X=4)+P(X=5)+(X=6)+P(X=7)` `=3k+k^(2)+2k^(2)+7k^(2)+k` `=(3)/(10)+(1)/(100)+(7)/(100)+(1)/(10)` `=(4)/(10)+(1)/(10)=(5)/(10)=(1)/(2)` |
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