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Elastic headon collision, consider two particles one is moving and another one is stationary with their respective masses m and M/m. A moving particle meets collides elastically on stationary particle in the opposite direction. Find the kinetic energy of the stationary particle after a collision. |
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Answer» Solution :mass of the moving particle `m_(1)` = m (say) mass of the stationary particle `m_(2) = 1/m M` Velocity of the moving particle before collision = `v_(1i)` (say) Velocity of the stationary particle before collision = `v_(2I)` = 0 Velocity of the stationary particle after collision = `v_(2F)` (say) `v_(2f) = (m_(2)-m_(1))/(m_(1)+m_(2)) v_(2i) + (2m_(1))/(m_(1)+m_(2)) v_(1i) ("or") v_(2f) = 0 + (2M)/(m+M/m) v_(1i) = (2m)/(m+1) v_(1i)` KINETIC ENERGY of the stationary particle after a collision `=1/2 M/m ((2m)/(m+1) v_(1i))^(2) = (4m)/((1+m)^(2)) xx 1/2 M v_(1i)^(2)` `= (4m)/((1+m)^(2)) xx` kinetic energy of moving particle before collision |
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