InterviewSolution
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InterviewSolution
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Electric field intensity ‘E’ at a point P (Figure) at a perpendicular distance ‘r’ from an infinitely long line charge X’X having linear charge density λ is given by :(A) E = \((\frac{1}{4\pi\in_0})\; \frac{2\lambda}{r^2}\)(B) E = \((\frac{1}{4\pi\in_0})\; \frac{2\lambda}{r}\)(C) E = \((\frac{1}{4\pi\in_0})\; \frac{\lambda}{r^2}\)(D) \((\frac{1}{4\pi\in_0})\; \frac{\lambda}{r^2}\) |
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Answer» (B) E = \((\frac{1}{4\pi\in_0})\; \frac{2\lambda}{r}\) |
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