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Electricity - PhsycisWhen a current of 0.5 A passes through a conductor for 5 minutesand the resistance of the conductor is 12Ω, the amount of heatproduced is |
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Answer» here I = 5^2 R = 12 T = 5 min = 300 sec using this formula I^2× R × T 0.5×0.5 × 12 × 300 0.25 × 12 × 300 900Joule Explanation: i hope it is helpful for you |
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