Electrode potential of `Zn^(2+)//Zn` is -0.76V and that of `Cu^(2+)//Cu` is +0.34V. The EMF of the cell constructued between these two electrodes isA. 1.10VB. 0.42VC. `-1.1V`D. `-0.42V`

Electrode potential of `Zn^(2+)//Zn` is -0.76V and that of `Cu^(2+)//C

1.	Electrode potential of `Zn^(2+)//Zn` is -0.76V and that of `Cu^(2+)//Cu` is +0.34V. The EMF of the cell constructued between these two electrodes isA. 1.10VB. 0.42VC. `-1.1V`D. `-0.42V`
Answer» Correct Answer - A `E_(cell)^(@)=E_("cathode")^(@)-E_("anode")^(@)=0.34-(0.76)=1.10V`

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Electrode potential of `Zn^(2+)//Zn` is -0.76V and that of `Cu^(2+)//Cu` is +0.34V. The EMF of the cell constructued between these two electrodes isA. 1.10VB. 0.42VC. `-1.1V`D. `-0.42V`

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