Electrolysis of 50%" "H_(2)SO_(4) produces

1.	Electrolysis of 50%" "H_(2)SO_(4) produces
Answer» `H_(2)S_(2)O_(8)` at ANODE `H_(2)SO_(5)` at cathode `H_(2)` at anode `H_(2)O_(2)` at anode & Cathode Answer :A

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