Electrolysis of dilute aqueous `NaCl` solution was carried out by passing `10mA` current. The time required to liberate `0.01mol` of `H_(2)` gas at the cathode is `(1F=96500C mol ^(-1))`A. `9.65xx10^(4)s`B. `19.3xx10^(4)s`C. `28.95xx10^(4)s`D. `38.6xx10^(4)s`

Electrolysis of dilute aqueous `NaCl` solution was carried out by pass

1.	Electrolysis of dilute aqueous `NaCl` solution was carried out by passing `10mA` current. The time required to liberate `0.01mol` of `H_(2)` gas at the cathode is `(1F=96500C mol ^(-1))`A. `9.65xx10^(4)s`B. `19.3xx10^(4)s`C. `28.95xx10^(4)s`D. `38.6xx10^(4)s`
Answer» Correct Answer - b `2H_(2)+e^(-)rarr H_(2)+2overset(c-)(O)H` For `0.01 mol H_(2),0.02mol ` of electrons are consumed. Charge required `-0.02xx96500C=Ixxt` Time required `=(0.02xx96500)/(10xx10^(-3))=19.3xx10^(4)s`

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Electrolysis of dilute aqueous `NaCl` solution was carried out by passing `10mA` current. The time required to liberate `0.01mol` of `H_(2)` gas at the cathode is `(1F=96500C mol ^(-1))`A. `9.65xx10^(4)s`B. `19.3xx10^(4)s`C. `28.95xx10^(4)s`D. `38.6xx10^(4)s`

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