Electrolysis of dilute aqueous `NaCl` solution was carried out by passing `10mA` current. The time required to liberate `0.01mol` of `H_(2)` gas at the cathode is `(1F=96500C mol ^(-1))`A. `9.65 xx 10^(4)`secB. `19.3 xx 10^(4)` secC. `28.95 xx 10^(4)`secD. `38.6 xx 10^(4)`sec

Electrolysis of dilute aqueous `NaCl` solution was carried out by pass

1.	Electrolysis of dilute aqueous `NaCl` solution was carried out by passing `10mA` current. The time required to liberate `0.01mol` of `H_(2)` gas at the cathode is `(1F=96500C mol ^(-1))`A. `9.65 xx 10^(4)`secB. `19.3 xx 10^(4)` secC. `28.95 xx 10^(4)`secD. `38.6 xx 10^(4)`sec
Answer» Correct Answer - B No. of Faraday of electricity ot liberate `0.01` Mole `= 0.01 xx 2F = 0.02F` `=2 xx 10^(-2) xx 9600 = 1930` coulomb `A = 10` miliampere `= 0.01` ampere `Q = 1 xx t` `t = (Q)/(I) = (1930)/(0.01) = 1.93 xx 10^(5) = 19.3 xx 10^(4)` sec

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Electrolysis of dilute aqueous `NaCl` solution was carried out by passing `10mA` current. The time required to liberate `0.01mol` of `H_(2)` gas at the cathode is `(1F=96500C mol ^(-1))`A. `9.65 xx 10^(4)`secB. `19.3 xx 10^(4)` secC. `28.95 xx 10^(4)`secD. `38.6 xx 10^(4)`sec

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