Electrolysis of X gives Y at anode. Vacuum distillation of Y gives H_(2)O_(2) The number of peroxybonds present in X and Y. Then x + y is?

Electrolysis of X gives Y at anode. Vacuum distillation of Y gives H_(

1.	Electrolysis of X gives Y at anode. Vacuum distillation of Y gives H_(2)O_(2) The number of peroxybonds present in X and Y. Then x + y is?
Answer» SOLUTION :`X = H_2SO_4, Y = H_2S_2O_8`