Electromagnetic radiation of wavelength 663 nm is just sufficient to i – InterviewSolution

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1.	Electromagnetic radiation of wavelength 663 nm is just sufficient to ionise the atom of metal A. The ionization energy of metal A in kJ mol−1 is (Rounded - off to the nearest integer)[h=6.63×10−34Js,c=3.00×108ms−1,NA=6.02×1023mol−1]
Answer» Electromagnetic radiation of wavelength $663 n m$ is just sufficient to ionise the atom of metal $A$ . The ionization energy of metal $A$ in $k J m o l^{- 1}$ is (Rounded - off to the nearest integer) $[h = 6.63 \times 10^{- 34} J s, c = 3.00 \times 10^{8} m s^{- 1}, N_{A} = 6.02 \times 10^{23} m o l^{- 1}]$

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