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Electromagnetic radiationof wavelength242nm isjustsufficientto ionise thesodiumatom .Calculatethe ionisation energyofsodiumin Kj mol^(-1)

Answer»

Solution :where `lambda= 242nm =242 xx 10^(9) m`wavelengthper photon`E= (hc )/(lambda ) ` permoleE = `(N_(A) hc )/(lambda )`
`n=6.626 xx 10^(34)Js`
`c=3.0xx 10^(8) m`
`N_(A)= 6.022xx 10^(23)` permole
`=(6.022 xx 10^(23) mol^(1)xx 6.626 xx 10^(34)js xx3.0 xx 10^(8) MS^(-1)J)/( (242 xx 10^(9) m))`
`=494.7 xx KJ mol^(-1)495kJ mol^(1)`
Ionisationenthalpy=495kJ `mol^(1)`


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