1.

Electron configuration of M olybdenum (Z = 42) is .....

Answer»

`[KR] 4d^(4) 5s^(2)`
`[Kr] 5s^(2) 4p^(4)`
`[Kr] 4d^(5) 5s^(1)`
`[Kr] 4d^(3) 5s^(2) sp^(-1)`

Solution :`E=(hc)/(LAMBDA),E_(1)=(hc)/(lambda_(1)),E_(2)=(hc)/(lambda_(2))`
`(6000A)/(3000A)=2/1 =2:1`


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