Electronegativity of carbon atoms depends upon their state of hybridisation. In which of the following compounds, the carbon marked with asterisk is most electronegative?

Electronegativity of carbon atoms depends upon their state of hybridis

1.	Electronegativity of carbon atoms depends upon their state of hybridisation. In which of the following compounds, the carbon marked with asterisk is most electronegative?
Answer» `CH_(3)-CH_(2) - ""^()C H_(2)-CH_(3)` `CH_(3)- ""^()C H= CH- CH_(3)` `CH_(3)- CH_(2)- C -= ""^()C H` `CH_(3)-CH_(2)-CH= ""^()C H_(2)` SOLUTION :(C ) `CH_(3)-CH_(2) - underset(underset(underset(sp)(uarr))(-))(C )-= underset(underset(underset("sp carbon")(uarr))(-))(""^()C)H` (A)`CH_(3)- CH_(2) - underset(underset(underset(sp^(3)"carbon")(uarr))(-))(""^()C)H_(2)-CH_(3)` (B) `CH_(3) - underset(underset(underset(sp^(2)"carbon")(uarr))(-))(""^()C)H= CH-CH_(3)` (D) `CH_(3)-CH_(2)-CH= underset(underset(underset(sp^(2)"carbon")(uarr))(-))(""^()C)H_(2)` but electronegativity `prop` % of s-orbital. `THEREFORE` sp carbon is MAXIMUM electronegative.