1.

Electronegativity of carbon atoms depends upon their state of hybridisation. In which of the following compounds, the carbon marked with asterisk is most electronegative ?

Answer»

`CH_(3)-CH_(2)-.^(**)CH_(2)-CH_(3)`
`CH_(3) - .^(**)CH = CH - CH_(3)`
`CH_(3)-CH_(2)-C -= OVERSET(**)(C)H`
`CH_(3)-CH_(2)-CH=overset(**)(C)H_(2)`

SOLUTION :Electronegatively increases as the state of hybridisation changes from `SP^(3)-sp^(2)-sp`. Thus, sp-carbon has the highest electronegatively, i.e., option (c) is CORRECT.


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