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Answer» `C lt N lt SI lt P` `N lt Si lt C lt P` `Si lt P lt C lt N` `P lt Si lt N lt C` Solution :Sinceelectronegativitiesincreases acrossa period, thereforeelectronegativityof N is MORETHAN thatC andelectronegativityof P ISMORE thatthan ofSi. Furthersinceelectronegativitydecreasesdowna groupthereforeelectronegativityof C ismorethan that ofSi andelectronegativityof N ismorethan THATOF P. combiningthe tworesults theelectronegativities of C, Si, Pand Nincreasesin the order : `Si lt P lt C lt N` i.e.,option ( c) is correct.
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