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Electronegativity values of some elements are given. Using these values, find whether the following compounds are ionic or covalent. (Electronegativity of Ca = 1, O = 3.5, C = 2.5, S = 2.58, H = 2.2, F = 3.98) i) Sulphur dioxide (SO2) ii) Water (H2O) iii) Calcium fluoride (CaF2) iv) Carbon dioxide (CO2) |
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Answer» (i) SO2 Electronegativity difference = 3.5 – 2.58 = 0.92 If the electronegativity difference is less than 1.7, it shows covalent character. (ii) Water (H2O) Electronegativity difference = 3.5 – 2.2 = 1.3 If the electronegativity difference is less than 1.7 it forms covalent compounds. (iii) CaF2 Electronegativity difference = 3.98 -1.0 = 2.98 If the electronegativity difference is greater than 1.7 if forms ionic compounds. (iv) CO2 Electronegativity difference = 3.5 – 2. 5 = 1.0 If the electronegativity difference is less than 1.7 it shows covalent compounds. |
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