InterviewSolution
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InterviewSolution
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Electronic configuratios of four elements `A, B, C` and `D` are given below: (i) `1s^(2)2s^(2)2p^(6)` (ii) `1s^(2)2s^(2)2p^(4)` (iii) `1s^(2)2s^(2)2p^(6)3s^(1)` (iv) `1s^(2)2s^(2)2p^(5)` Which of the following is the correct order of increasing tendency of gain electron:A. AltCltBltDB. AltBltCltDC. DltBltCltAD. DltAltBltC |
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Answer» Correct Answer - A A is Ne(10):`1s^(2)2s^(2)2p^(6)` B is O(8):`1s^(2)2s^(2)2p^(4)` C is NA(11):`1s^(2)2s^(2)2p^(6)3s^(1)`D is `F(9):1s^(2)2s^(2)2p^(5)`, Noble gases (A)have completely filled orbitals hence,they have no tendency to gain electrons. Element C prefers to lose electron `(3s^(1))` to attain stable noble gas configuration. Element D has Only 1 electron less than stable noble gas configuration.Thus,it has greater tendency to gain electron than element B which has 2 electrons less than noble gas configuration.Thus,the correct order of increasing tendency to gain electron is:AltCltBltD |
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