1.

Electronicconfiguationof four elements B, C and Dare givenbelow : A. 1s^(2)2s^(2)2p^(6)B. 1s^(2)2s^(2) 2p^(4) C. 1s^(2)2s^(2)2p^(6)3s^(1)D.1 s^(2)2s^(2)2p^(5) whichof the followingis thecorrectorderincreasingtendencyto gainelectron :

Answer»

`A lt C lt B lt D`
`A lt B lt C lt D`
`D lt B lt C lt A`
`D lt A lt B lt C`

Solution :Electronicconfigurationsof elementssuggestthat A is a noblegas (i.e., Ne) B is oxygen(Group 16), Cis an ALKALI metal( group1) andDis a halogen( group 17) .
(i) Noblegases have no tendencyto gain electronssince alltheirorbitalsare completely FILLED. Thuselement A hashte leastelectron gainenthalpy.
Nowsinceelement D hasone electron lessand elementBhastwoelectrons LESSTHAN thecorrespondingnoblegasconfigurationthereforeelementD hasthe highestelectrongainenthalpyfollowedby ELEMENT B.
(iii) SinceelementC hasoneelectron in thes-orbitaland henceneedsone moreelectron to complete it thereforeelectrongainenthalpy of C islessthan that of elementB. Combing all the factsgivenabovetheelectron gain enthalpy of thefour elementsincreasesin theorder `: A lt C lt b lt D,` i.e.,option (a) is correct .


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