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Electrons are accelerated through a potential difference of `150V`. Calculate the de broglie wavelength. |
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Answer» `V=150V,h=6.62xx10^(-34)Js,m=9.1xx10^(-31)kg,e=1.6xx10^(-19)C` `:.lambda=h/sqrt(2Vem)=(6.62xx10^(-34))/sqrt(2xx9.1xx10^(-31)xx1.6xx10^(-19)xx150)=1overset(0)A` |
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