1.

Element P Q R SMass NO. 12 20 23 35No. of neutron 6 10 12 18a) write electronic configuration and atomic numberb) which of these is chemically inertplease explain how to solve

Answer»

(a)

Atomic NUMBER (Number of protons) :

P = 6 (12-6)

Q = 10 (20-10)

R = 11(23-12)

S = 17(35-18)

Electronic CONFIGURATION :

P = 2,4

Q = 2,8

R = 2,8,1

S = 2,8,7

(B) Note from above part that the compound Q has a configuration of 2,8 which has all shells FILLED and thus the compound Q is inert.

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