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Elements A and B form two compounds `B_2A_3` and `B_2A`. If 0.05 moles of `B_2A_3` weigh 9.0 g and 0.10 mole of `B_2A` weigh 10 g, then atomic weight of A and B are :-A. 20 and 30B. 30 and 40C. 40 and 30D. 30 and 20 |
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Answer» Correct Answer - C 0.05 mol `B_2A_3` = 9 g 1 mol `B_2A_3 = 9/0.05 `= 180 g `therefore` 2B+3A = 180 ….(i) 0.10 mol `B_2A`=10 g 1 mol `B_2A=10/0.10`=100 g `therefore` 2B +A = 100 ….(ii) On solving (i) & (ii) A = 40, B = 30 |
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