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Elevation in boililng point was `0.52^(@)C` when 6 gm of a compound X was dissolved in 100 gm of water. Molecular weight of X is (`K_(b)` for water is 0.52 per 1000 gm of water)A. 120B. 60C. 180D. 600 |
Answer» Correct Answer - B `Delta T_(b)=(100xx K_(b)xx w)/(m xx W) therefore 0.52=(100xx5.2xx6)/(m xx 100)` `m=(100xx5.2xx6)/(0.52xx100)=60`. |
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